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70x^2+140x-9=0
a = 70; b = 140; c = -9;
Δ = b2-4ac
Δ = 1402-4·70·(-9)
Δ = 22120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{22120}=\sqrt{4*5530}=\sqrt{4}*\sqrt{5530}=2\sqrt{5530}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-2\sqrt{5530}}{2*70}=\frac{-140-2\sqrt{5530}}{140} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+2\sqrt{5530}}{2*70}=\frac{-140+2\sqrt{5530}}{140} $
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